OCTET STRING value like 73:63:6f:74:74:79 can be converted into a readable string (DisplayString) by formatting it according to the DisplayString textual convention.

There are two easy ways to do this: you can use the <cstdio> facilities or the <iostream> library. In general, you should prefer the <iostream> library. The <iostream> library allows you to convert pretty much anything to a std::string using the following syntax (the example converts a double, but you could substitute pretty much anything that prints using the << operator): The std::ostringstream object o offers formatting facilities just like those for std::cout. See similar questions...

I am including the header file <string>, and I am using the string class, but the code doesn't compile? (namespace resolution, having the std:: topics) How do I use unique() with vectors? (answered only once, but still a good question to have due to people not knowing that it's possible to do) See similar questions...

My script is filling up the vacmAccessTable (in the vacmMIBObjects) > with values (that works fine). But when the script deletes the > table rows, an error occurs. > > Here is the error that is printed as output from the script: > {Failed INDEX simulation for table} > while executing > "mimic value instances 1.3.6.1.6.3.16.1.4.1.9" >... In your script, adding a new instance to the vacmAccessTable is not working correctly i.e. See similar questions...

Private Sub Page_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load Private Sub ddlCulture_SelectedIndexChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles ddlCulture.SelectedIndexChanged See similar questions...

Well, printf does it for output, so look at its related function named sprintf that "prints formated output to a string." See similar questions...

It's easy. Use sprintf. For example: char string1[50]; char string2[50]; short int var1; float var2; ... sprintf (string1, "%d", var1); sprintf (string2, "%f", var2); See similar questions...

You want to make a function that converts from a type to another. Like from std::string to int, or the other way around. This can be done using std::stringstream and insertion / extraction operators. Just as above, templates will prove of great help: Its usage is not as straightforward as the above explained max template. Normally, you would want to call it like "int value = lexical_cast( myStdString );". There is, however, a problem. See similar questions...

There are two easy ways to do this: you can use the <cstdio> facilities or the <iostream> library. In general, you should prefer the <iostream> library. See similar questions...

If you are reading a host's address from the command line, you may not know if you have an aaa.bbb.ccc.ddd style address, or a host.domain.com style address. What I do with these, is first try to use it as a aaa.bbb.ccc.ddd type address, and if that fails, then do a name lookup on it. Here is an example: Converts ascii text to in_addr struct. NULL is returned if the address can not be found. See similar questions...

If what you have is a url datatype with url encoded characters you can just use TO-STRING (which is short for MAKE STRING!). If it is a string that has URL-encoded characters, see the cgidecode.r script in the script library on REBOL's website for an example. present it uses the local operating system default. For example, on Unix it's just LF. On windows it's CRLF. See similar questions...

This question arises from a misunderstanding from Windows users. Not their fault, as there is no reason they should know what a .dmg file is. Here's the short description: a .dmg file is not a picture, but a Disk iMaGe file. You double-click it, and it mounts on the desktop as an ejectable disk, much like that old jurassic technology, the floppy. It's merely a convenient way to transfer files over the web. As far as I know, it remains an OS X only technology. See similar questions...

Insert a column after the Unix timestamp and enter the following formula into the first blank cell of the new column: =((A2/1000)+(-8*3600)+((365*70+19)*86400))/86400 Copy this formula down the entire column ensuring that the A2 element of the formula increases down the column. Candela Technologies, Suite A, 2026 Main Street, Ferndale, WA 98248, USA | www.candelatech.com | sales@candelatech.com | +1 360 380 1618 (PST, GMT -8) See similar questions...

Octetruss, to use the trademarked moniker, is an OCtahedral and TETrahedral complementary grid implemented in such a way as to form a structural truss. A truss is an engineering mechanism for dispersing loads across a relatively long span, to enable coverage of large, primarily horizontal areas with a minimum of underpinning supports (posts). Most trusses appear to be arranged to act independently of one another, whereas the members of an Octetruss are all part of the whole unit. See similar questions...

In general, when you want to convert from one type to another, the first class to look at is System.Convert. It has a load of static methods which are likely to help you. If you're converting from a String, you could also check whether the type that you want to convert to has a Parse method or something similar - for instance, I usually use DateTime.ParseExact to convert from a String to a DateTime. See similar questions...

Some libraries have routines strupr and strlwr or strupper and strlower, but these are not Standard or portable. It's a straightforward exercise to write upper/lower-case functions in terms of the toupper and tolower macros in <ctype.h>; see also question 13.5. (The only tricky part is that the function will either have to modify the string in-place or deal with the problem of returning a new string; see question 7.5a. See similar questions...

There are several ways. The most straightforward is: String myString = numString.trim(); int i = Integer.parseInt(myString); long l = Long.parseLong(myString) or String myString = numString.trim(); i = Integer.parseInt(myString,myIntRadix); Note 1: There is a gotcha with parseInt - it will throw a NumberFormatException for String values in the range "80000000" to "ffffffff". You might expect it to interpret them as negative, but it does not. The values have to be "-80000000" . See similar questions...

Try any of these: String s = String.valueOf(i); or String s = Integer.toString(i); or String s = Integer.toString(i, radix); or // briefer but may result in extra object allocation. String s = "" + i; Note: There are similar classes for Double, Float, Long, etc. See similar questions...

There is no 'right' answer to this question; many lisp programmers have rolled their own solution in the past, and others are of the view that it should never be necessary, as long as all sequence functions are used with consistent :start and :end arguments. However, a community-based 'standard' was developed in June/July 2001 on comp.lang.lisp; known as SPLIT-SEQUENCE (formerly PARTITION), it works as follows in its simplest form: split-sequence #\Space "A stitch in time saves nine. See similar questions...