A.java public class A { public int mtdA(int x) { return x + 3; } public int mtdB(int x, int y) { return x + y; } } class B extends A { /* $ javac A.java A.java:23: mtdA(int) in B cannot override mtdA(int) in A; attempting to use incompatible return type found : double required: int public double mtdA(int x) { ^ 1 error public double mtdA(int x) { return x + 0.2; } */ // Compiled OK public double mtdB(int x) { return x + 0.2; } } A.

Overriding is what we do when we derive subtypes from supertypes and specialize the subtype's behaviour by means of implementing in the subtype a specialized version of a method inherited from the supertype. Overriding is one of the key concepts of object-oriented programming. See similar questions...

You can't call an arbitrary C function, but you can load and call one that is written to Icon's specifications. A tutorial appears in Icon Analyst 36. Some examples can be found in the cfuncs and packs/loadfuncs directories of the Icon program library. The Jcon implementation allows Icon programs to call Java code that is written to Jcon specifications. See similar questions...

This function allows to force a machinery stop, due to material present in the dangerous area after the MUTING function. The OVERRIDE function allows the forced safety device activation even in presence of interrupted beams. The activation requests a precise procedure; the START and TEST inputs have to be contemporary activated during the initial autotest phase and kept pressed until all the material has left the dangerous area. See similar questions...

Because the decision regarding overriding vs. overloading is based on the generic type, not on any instantiation thereof. Sometimes, when you believe you override a method inherited from a supertype you inadvertantly overload instead of override the inherited method. This can lead to surprising effects. Let us study an example. The problem is that the subclass's reset method does not override the superclass's reset method, but overloads it instead. See similar questions...

sense #2:overloading methods will have the "same name" but different signature. overriding methods will have the "same name" and same signature. Except these above, there is nothing in common between them. Please read some more from the following QAs. When methods are defined with the same name, but different signature, they are just name overloading, nothing can hide anything else. It is irrelevant it is in a derived class or not. He will be right back. See similar questions...

This FAQ entry discusses the relationship between generic methods in super- and subtypes with respect to overriding and overloading. Say, we have a supertype with generic methods and we intend to override the generic methods in a subtype. Which subtype methods are considered overriding versions of the the generic supertype methods? FAQ entry FAQ823 discusses which non-generic methods in a subtype override a generic method in a supertype. See similar questions...

When the subtype's method has a signature that is a subsignature of the supertype's method and the two methods have compatible return types and throws clauses. identical to the erasure of the supertype's method's signature. It is said that the subtype method has a subsignature or that the two signatures are override-equivalent . Both methods have the same signature, namely method(String) , and for this reason the subclass's method overrides the superclass's method. See similar questions...

Use the abstract modifier on the method. The class must also be marked as abstract (naturally). Note that abstract methods cannot have an implementation (unlike pure virtual C++ methods). See similar questions...

Amulet methods use a pointer to the C++ function in order to store the method in a slot of the Amulet object. As discussed in the standard C++ FAQs, you cannot generate a pointer to a C++ member function since it wouldn't know which C++ object the method should be associated with. Instead, you should store the C++ object into a slot of the object, (see FAQ item 5. See similar questions...

Suppose I'm writing an ASM function 'foo(n)' which accepts an argument (a string, for example). I want to make 'foo(n)' return 'foo(n)' (the call itself) when 'n' is of type "VAR" (i.e. if nothing has been assigned to 'n' yet)... This is quite easy, if you know in advance the name of the program. Suppose, that your program name is "example". See similar questions...

The C. Link (control link) port interconnects two or more 7-Series recorders and locks their word clock. on the 744T the C. Link also carried time code output. C. Link is also "big brother", with the ability to retrieve all kinds of data stored in the unit's EEPROM. It is our primary test/diagnostic input. In the future, we will allow third-party access to features available on the C. Link port. The new CL-1 accessory provides for keyboard control and remote roll via C. Link. See similar questions...

This FAQ entry discusses the relationship between generic and non-generic methods with respect to overloading. Say, we have a supertype with generic methods and we intend to override the generic methods in a subtype. See similar questions...

This FAQ entry discusses whether a generic method in a subtype can override an non-generic method inherited from a supertype. We have seen in FAQ823 that the converse is possible, namely that a regular, non-generic method in a subtype can override a generic method inherited from a supertype. It raises the question whether the same is true if the roles are flipped and a generic method in a subtype attempts to override a non-generic method from a supertype. See similar questions...

This FAQ entry discusses whether and when methods of a regular, non-generic subtype override methods inherited from a generic supertype. The question comes up because overriding requires that the method signatures are override-equivalent. If the supertype is generic then its method signatures might involve a type parameter. At the same time, the subtype is non-generic and its method signatures will not involve type parameters. See similar questions...

The answer is: Yes, methods of a generic subtype can override methods of a generic supertype, but it is not always trivial to get it right and it is common that mistakes are made and that overriding is confused with overloading. The subtype methods override the corresponding supertype methods. The generic subtype derives from a certain instantiation of the supertype, namely Super<S> in the example, where S is the subtype's type parameter. See similar questions...

The PyObject_CallMethod() function can be used to call an arbitrary method of an object. The parameters are the object, the name of the method to call, a format string like that used with Py_BuildValue(), and the argument values: PyObject * PyObject_CallMethod(PyObject *object, char *method_name, char *arg_format, ...); This works for any object that has methods -- whether built-in or user-defined. You are responsible for eventually Py_DECREF'ing the return value. To call, e.g. See similar questions...

override may grant a student permission to take a course if they have not taken the required prerequisite course or if the course is filled at the time of registration. The program director is responsible for approving and disapproving overrides. See similar questions...